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xcode NSMutableURLRequest,在POST方式下传递参数

时间:2022-06-25 23:51:06 编辑:袖梨 来源:一聚教程网

 代码如下 复制代码
- (IBAction)upload:(id)sender {
 
    NSString *post = nil; 
 
    post = [[NSString alloc] initWithFormat:@"message=%@",@"hello,world."];
 
    NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES]; 
 
    NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]]; 
 
    NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init] ; 
 
    [request setURL:[NSURL URLWithString:@"http://localhost/kids/sendimg.php"]]; 
 
    [request setHTTPMethod:@"POST"];
 
    [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; 
 
    [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"]; 
 
    [request setHTTPBody:postData]; 
 
    //[NSURLConnection connectionWithRequest:request delegate:self ]; 
 
 
 
    //同步请求的的代码
 
    //returnData就是返回得到的数据
 
    NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];
 
    NSString *result = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding];
 
 
 
    if(returnData)
 
 
 
     {
 
 
 
     NSLog(@"SOAP 返回 = %@",result);
 
 
 
     }
 
 
 
     else
 
 
 
    {
 
 
 
    NSLog(@"error!");
 
 
 
     }
 
}

php

 代码如下 复制代码

print_r($_POST);
?>
2014-09-18 15:16:21.346 Test9[31505:ef03] SOAP 返回 = Array
(
[message] => hello,world.
)

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