java中servlet得到完整的URL的例子

// Example: http://myhost:80**8*0/people?lastname=Fox&age=30

String uri = request.getScheme() + "://" + // "http" + "://
request.getServerName() + // "myhost"
":" + request.getServerPort() + // ":" + "8080"
request.getRequestURI() + // "/people"
(request.getQueryString() != null ? "?" +
request.getQueryString() : ""); // "?" + "lastname=Fox&age=30"
.getScheme() will give you "https"if it was a https://dom**ai*n request.
.getServerName() gives domain on http(s)://domain.
.getServerPort() will give you the port.

String uri = request.getScheme() + "://" +
request.getServerName() +
("http".equals(request.getScheme()) && request.getServerPort() == 80 || "https".equals(request.getScheme()) && request.getServerPort() == 443 ? "" : ":" + request.getServerPort() ) +
request.getRequestURI() +
(request.getQueryString() != null ? "?" + request.getQueryString() : "");