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sql insert into select 的用法

时间:2022-06-29 10:10:43 编辑:袖梨 来源:一聚教程网

INSERT INTO SELECT语句

 语句形式为:Insert into Table2(field1,field2,...) select value1,value2,... from Table1

 要求目标表Table2必须存在,由于目标表Table2已经存在,所以我们除了插入源表Table1的字段外,还可以插入常量

SQL>
SQL>
SQL> CREATE TABLE employee (
  2  id          number,
  3  name        varchar(100),
  4  birth_date  date,
  5  gender      varchar2(30) );

Table created.

SQL>
SQL>
SQL> INSERT INTO employee (id,name,birth_date,gender )
  2  SELECT 200,'Chris',NULL,'MALE' from   DUAL;

1 row created.

SQL>
SQL>
SQL> drop table employee;

Table dropped.

SELECT INTO FROM语句

      语句形式为:SELECT vale1, value2 into Table2 from Table1

      要求目标表Table2不存在,因为在插入时会自动创建表Table2,并将Table1中指定字段数据复制到Table2中。示例如下:


带有条件选择where

SQL>
SQL> CREATE TABLE employee (
  2  id          number,
  3  name        varchar(100),
  4  birth_date  date,
  5  gender      varchar2(30) );

Table created.

SQL>
SQL> INSERT INTO employee (id,name,birth_date,gender ) SELECT 300,'H',NULL,'MALE' from   dual d
  2  where not exists (SELECT 1 FROM   employee x WHERE  x.id = '300' );

1 row created.

SQL>
SQL> select * from employee;

    ID
------
NAME
----------------------------------------------------------------------
BIRTH_DATE GENDER
---------- ------------------------------
   300
H
null       MALE

Insert bulk by insert ... into ... select

SQL>
SQL> CREATE TABLE project (
  2    pro_id              NUMBER(4),
  3    pro_name            VARCHAR2(40),
  4    budget          NUMBER(9,2),
  5    CONSTRAINT project_pk   PRIMARY KEY (pro_id)
  6  );

Table created.

SQL>
SQL>
SQL> INSERT INTO project(pro_id, pro_name, budget)VALUES (1001, 'A',12345);

1 row created.

SQL> INSERT INTO project(pro_id, pro_name, budget)VALUES (1002, 'ERP',23456);

1 row created.

SQL> INSERT INTO project(pro_id, pro_name, budget)VALUES (1003, 'SQL',34567);

1 row created.

SQL> INSERT INTO project(pro_id, pro_name, budget)VALUES (1004, 'CRM',45678);

1 row created.

SQL> INSERT INTO project(pro_id, pro_name, budget)VALUES (1005, 'VPN',56789);

1 row created.

SQL>
SQL>
SQL> SET ECHO ON
SQL> INSERT INTO PROJECT (pro_id, pro_name)
  2     SELECT pro_id+8000,
  3            SUBSTR(pro_name,1,31) || ' Overhead'
  4     FROM project;

5 rows created.

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