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我有一个加密方法,欢迎大家指正

时间:2022-07-02 23:58:09 编辑:袖梨 来源:一聚教程网

<%
IF Request("Action")=1 then
Dim String,StringLen,i,StringNumTmp,StringRndNum,ResultString,j
String = Request("Pass")       '密码字符串
'开始计算字符数据
StringLen = Len(String)
For i = 1 to StringLen
    StringNumTmp = Asc(Mid(String,i,1))
    
    Randomize
    StringRndNum=Int((18-1)*Rnd+1)
    
    if Len(StringNumTmp + StringRndNum) < 3 then
    
    For j = 1 to 3 - Int(Len(StringNumTmp + StringRndNum))
    StringNumber = "0" & (StringNumTmp + StringRndNum)
    Next
    
    Else
    
    StringNumber = StringNumTmp + StringRndNum
    
    End if
    
    ResultString = ResultString & Chr(StringNumTmp - StringRndNum) & StringNumber
Next
Response.write "加密后结果:" & ResultString       '输出结果
%>


<%
'开始破解
For i = 1 to Len(ResultString) Step 4
    PString = Left(Mid(ResultString,i,4),1)
    
    PStringNum1 = Asc(PString)
    
    PStringNum2 = Int(Right(Mid(ResultString,i,4),3))
    
    PStringNum = (PStringNum1 + PStringNum2) / 2
    
    PString1 = PString1 & Chr(PStringNum)
Next
Response.write "破解后结果:" & PString1
End if
%>



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